2^4-x-2^3-x=1/8

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Solution for 2^4-x-2^3-x=1/8 equation:



2^4-x-2^3-x=1/8
We move all terms to the left:
2^4-x-2^3-x-(1/8)=0
We add all the numbers together, and all the variables
-x-x+2^4-2^3-(+1/8)=0
We add all the numbers together, and all the variables
-2x+8-(+1/8)=0
We get rid of parentheses
-2x+8-1/8=0
We multiply all the terms by the denominator
-2x*8-1+8*8=0
We add all the numbers together, and all the variables
-2x*8+63=0
Wy multiply elements
-16x+63=0
We move all terms containing x to the left, all other terms to the right
-16x=-63
x=-63/-16
x=3+15/16

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